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On Monday, 29 April 2013 14:30:13 UTC+5:30, colmkav wrote:
>
> Hi, I am trying to execute this function to return the column number of a
> heading. However although the value is correctly 3 when it reaches the end
> of the function it becomes 0 when I set it to iFund2Col after leaving the
> function. What am I doing wrong here?
>
> Sub test()
> Dim iFund2Col As Integer
> Dim ws As Worksheet
> Dim wb As Workbook
> Set wb = Workbooks.Open("H:\\fnd_CRLQRPT020130424.xls")
> Set ws = wb.Worksheets(1)
>
> If (iFund2Col = GetHeadingColumnNumber(ws, "Fund")) < 0 Then
> MsgBox "ERROR"
> End If
>
> End Sub
>
> Function GetHeadingColumnNumber(ByVal ws As Worksheet, sHeading As String)
> As Integer
> Dim rg As Range
> Dim iColumnNumber As Integer
> GetHeadingColumnNumber = -1
>
> Set rg = Nothing
> On Error Resume Next
> Set rg = ws.Range("1:1").Find(What:=sHeading, LookAt:=xlWhole)
> On Error GoTo ERROR_HANDLER
> If rg Is Nothing Then
> Err.Raise -99, "GetHeadingColumnNumber", "Unable to find heading:
> " & sHeading & "in worksheet:" & ws.Name
> End If
>
> GetHeadingColumnNumber = rg.Column
>
> Exit Function
>
> ERROR_HANDLER:
> ErrorHandler Err
> End Function
>
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