Mr. Emamuddin,
I'm looking through your code and have encountered some issues.
First, your sample file is only one sheet,with a Header in row 1 and 2 rows of 
data in 24 columns (A:X)
In your code, you use:
sc = Sheets.CountWhich, of course sets the variable "sc" equal to the total 
number of sheets.
but, when you use:    For c = 1 To 27
         cold(c) = Sheets(sc).Cells(c, 3).Value
    Next c
You're loading data from the LAST sheet of the workbook.Using your sample file, 
having only 1 sheet, this will use this sheet.However, your variables "c" and 
"cold" IMPLY "column" and "Column-Old"
but your in your loop: the Cells() function syntax is "Cells(row,column)which 
means that your loop is loading ROWS 1 to 27, column 3 (C) into the cold() 
array.
Your next loop:For b = lr - (size - 1) To lr
will fail with your sample file, since:lr = 4size = 100
so your loop is:For b = -95 to 4
In the first iteration, it will fail for row -95 of the cells() function.
Of course, I cannot test the code:  Workbooks.Open 
Filename:=Sheets(sc).Cells(1, 8), Password:=Sheets(sc).Cells(10, 8).Value
because the sample file does not have a filename in row 1, column "H"
I suggest you utilize the "breakpoint" functionality of the VBEditor and step 
through your program one line at a time and monitor the variables.
also, to help you with reading the code, try using the column LETTER in the 
cells() function when you can.
That is: Cells(1,"C") for row 1, column C instead of cells(1,3)You're less 
likely to confuse the row/column.
Of course, this doesn't apply when you're referring to the array index.
Paul-----------------------------------------
“Do all the good you can,
By all the means you can,
In all the ways you can,
In all the places you can,
At all the times you can,
To all the people you can,
As long as ever you can.” - John Wesley
----------------------------------------- 

    On Wednesday, October 19, 2016 7:39 AM, Emamuddin Shah <emt...@gmail.com> 
wrote:
 

 there are x rows more than 100 in that i want to update 50 rows or 20 rows 
whatever.
iam able to get row details in array, but those details are not getting updated 
on next workbook

i have attached exscel sheet format which iam using, there is 1 more similar 
file with coloumns shuffeled 
please find attached

On Tuesday, October 18, 2016 at 7:11:00 PM UTC+5:30, Paul Schreiner wrote:
I'm trying to follow.There are easier ways to load the array from the cell 
values, but I'll get to that later.
But:You said that you have 50 rows. that means that with:lr = 
Activecell.Cells(.Rows.count, "A").End(xlUp).Row + 1
lr (last row) = 51you set:size = 100So, for your loop:For b = lr - (size - 1) 
To lr
b = 51 -(100-1) to 51orb = -48 to 51
so this should produce an error when you execute:
cmail(ab) = Cells(b, cold(7)).Value
What are the values in column "C" rows 1-27?from your use of cold(), they must 
be integers.
Can you send me a sample file?we can step through it and figure out what 
happens in the second iteration.
Paul------------------------------ -----------
“Do all the good you can,
By all the means you can,
In all the ways you can,
In all the places you can,
At all the times you can,
To all the people you can,
As long as ever you can.” - John Wesley
------------------------------ ----------- 

    On Tuesday, October 18, 2016 8:49 AM, Emamuddin Shah <emt...@gmail.com> 
wrote:
 

 ITS NOT UPDATED ALL 50 STRINGS ROW DETAILS.
IT IS UPDATING ONLY FIRST MATCHED STRING ROW. 

On Tuesday, October 18, 2016 at 6:13:56 PM UTC+5:30, Emamuddin Shah wrote:
Hello

Iam trying to Loop so that it matched a string and then fills cells in that row.
say i have 50 strings to be matched  and then update date on that row, data i 
have stored in ARRAY

here is my part of code where I am struck


++++++++++++++++++=
cm = 1

For i = 2 To lri


If Cells(i, 7) = cmail(cm) Then
Cells(i, 15).Value = stat1(cm)
Cells(i, 16).Value = stat2(cm)
Cells(i, 17).Value = ccdate(cm)
Cells(i, 18).Value = ctime(cm)
cm = cm + 1
End If

Next
++++++++++++++++++++++++++++++ +

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