https://bugs.exim.org/show_bug.cgi?id=2180

--- Comment #3 from Richard James Salts <[email protected]> ---
Never mind my previous comment. I realized that you have three cases:

(n=0) + 1 = sign the header even if it doesn't exist
(n>0) + 1 = double sign the header if it exists
(n>0) = just sign the header that exists allowing subsequent senders to add
additional copies of the header

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