On Friday 19 January 2007 02:27, Slava Pestov wrote:
> You have both apps/factory/ and apps/factory.factor. I don't like
> this.
With a system like vocabs, as part of the design process you have to make a
decision. How do you map vocabularies to files?
METHOD A:
USE: x => x/x.factor
USE: y => y/y.factor
USE: x.foo => x/foo/foo.factor
USE: x.foo.bar => x/foo/bar/bar.factor
This was my first mapping scheme. It's a simple function. It would solve the
annoyance of factory.factor and factory/ in the same directory. However there
was an even bigger annoyance. As you can see, each vocabulary get's it's own
directory. I thought about what this would be like with a system like the x
vocabulary and the associated hierarchy. I really like being able to open the
directory x/ and see all *.factor files that implement the sub vocabs of x.
With METHOD A, I'd see a bunch of directories, most of which only hold a
single file. It was this property, that the majority of directories would
only serve to hold a single file that made me look for another mapping
scheme.
METHOD B:
USE: x => x.factor
USE: y => y.factor
USE: x.foo => x/foo.factor
USE: x.foo.bar => x/foo/bar.factor
USE: x.foo.baaz => x/foo/baaz.factor
OK. This doesn't have the one directory per vocabulary problem. You open the
x/foo directory and you'll see the bar and baaz files. Nice. Slava opens libs
and sees x.factor and x/. Not so nice. :-) I thought the same thing. But I
realized that I'd have to put up with one annoyance or another. Either
annoyance comes from a using a strict function to map. The system yields
benefits that come from this discipline (and bondage! haha) but coders are so
used to adhoc organization of files that this seems more like a wart.
I have to think about the mapping method before I change things.
Sorry for the long explanation but I wanted you to see that this wasn't just
something I picked willy-nilly.
Ed
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