Is walking a call through supposed to insert breaks into quotations?
On Tue, Jul 29, 2008 at 4:27 PM, Slava Pestov <[EMAIL PROTECTED]> wrote:
> Here is my solution:
>
> "VVNFOiBrZXJuZWwgWyBbIGR1cCBjdXJyeSBdIGR1cCBjdXJyeSBd" base64> >string eval
> .
>
> Slava
>
> On Tue, Jul 29, 2008 at 5:55 PM, Paul Butler <[EMAIL PROTECTED]> wrote:
> > Hi,
> >
> > Here is a function to test whether a quotation, when called, returns
> itself
> > (apparently this is called a Quine
> > <http://en.wikipedia.org/wiki/Quine_(computing)<http://en.wikipedia.org/wiki/Quine_%28computing%29>
> >):
> >
> > USING: quotations
> > : quine? ( quotation -- bool ) dup call = ;
> >
> > It is an interesting puzzle to try to write one, so I won't paste my
> answer
> > in plaintext. However, the following evaluates to t.
> >
> > USING: base64 parser ;
> >
> "VVNJTkc6IGtlcm5lbCBxdW90YXRpb25zIGFycmF5cyA7IFsgWyBcIGR1cCBcIGNhbGwgXCA+cXVvdGF0aW9uIDRhcnJheSBdIGR1cCBjYWxsID5xdW90YXRpb24gXQ=="
> > base64> eval quine?
> >
> > If anyone comes up with another solution, I'd be very interested to see
> it.
> >
> > Cheers,
> > Paul
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