Heiko Carstens <[EMAIL PROTECTED]> writes: > > With binary interface I mean: the kernel image will be handled as binary blob > and the only things that need to be changed are: > - the command line -> always at 0x10480 > - size and position of the initrd -> always at 0x10408/0x10410 > There is no need to distinguish between 32/64bit kernel images since they > get treated exactly the same way. > Hope that clarifies things a bit or maybe I get you wrong? Uhmm..
A little. It sounds like you are handing off to a bootloader? The basic question is if I want to boot something other than the linux kernel with kexec will that work? Assuming the appropriate user space side is in place. I'm really trying to understand how you can execute either 32bit or 64bit code with the same binary interface. Is it something like ppc where the same instructions work regardless of mode? But even the ppc has a mode. Eric _______________________________________________ fastboot mailing list [email protected] https://lists.osdl.org/mailman/listinfo/fastboot
