Hello,
Thank you for the clarification.
So if I understand well, the strategy should be to pre-code all the possible
case of the function call, and then navigate between them with a selectn
function ?
something like
slider=int(hslider("",0,0,4,1));
(f(1),f(2),f(3),f(4),f(5)):selectn(5,slider):_
?
Pierre
> Hi Pierre,
>
> Pattern matching occurs at compile time while the slider can only change at
> run time. Take a look at the new selectn() function in math.lib for
> selecting among various cases at run time.
>
> Cheers,
> - Julius
>
> On Tue, Jun 14, 2016 at 1:10 PM Pierre Lecomte <pierre.leco...@gadz.org>
>
> wrote:
> > Hello,
> > I'm having some trouble with pattern matching and variable type :
> >
> > // Let's say I've a slider which I wish output Integer values :
> > slider=int(hslider("",1,1,3,1));
> >
> > // Now my pattern matching rule in a right order (specific rules first,
> > general
> > rule last)
> > f(1)= 1;
> > f(2)= 7;
> > f(3) = 2.25;
> > f(x) = 0;
> >
> > f(2) for example, I get 7, as expected. However, when I call f(slider), I
> > always get 0, as if the output of the slider is not and integer which
> > could
> > match my pattern matching rules..
> >
> > I think I miss something... any help ??
> >
> > Pierre
> >
> >
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patterns at an interface-level. Reveals which users, apps, and protocols are
consuming the most bandwidth. Provides multi-vendor support for NetFlow,
J-Flow, sFlow and other flows. Make informed decisions using capacity planning
reports. http://pubads.g.doubleclick.net/gampad/clk?id=1444514421&iu=/41014381
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