Hi, Oleg. I almost forgot faust, but everything looks correct to me... You can't > assume that > something(1) is equivalent to (1 : something(_)). > > Lets simplify your example: > > test(x) = (x , _ : -) ~ _; > > Now, > process = test(1) > > results in > > process = (1 , _ : -) ~ _; > > note that in this case "(1 , _ : -)" has a single input. > > while > > process = 1 : test(_); > > means > > process = 1 : ((_ , _ : -) ~ _); >
This is what I wasn't aware of: I thought that the wire would have simply been replaced by the signal provided with the sequential composition. Thanks for the explanation. D
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