Thanks!  A more complete test is to feed it a slow chirp:
f0 = 20.0;
fMax = 0.5 * ma.SR;
octavesPerSecond = 1.0;
fRatio = 2.0^(octavesPerSecond/ma.SR);
chirpFreq = 1-1' : *(f0) : + ~ *(fRatio);
freq = min(fMax, chirpFreq);
process = os.osccos(freq) : analytic;

On Thu, Jul 4, 2019 at 5:13 PM Dario Sanfilippo
<sanfilippo.da...@gmail.com> wrote:
>
> Hello, everybody.
>
> Here's yet another design to obtain analytic signals, taken from Olli's post: 
> https://dsp.stackexchange.com/questions/37411/iir-hilbert-transformer/59157#59157.
>
> analytic(x) =   real,
>
>                 imaginary
>
> with {
>
>     re_c = (0.47944111608296202665, 0.87624358989504858020, 
> 0.97660296916871658368, 0.99749940412203375040);
>
>     im_c = (0.16177741706363166219, 0.73306690130335572242, 
> 0.94536301966806279840, 0.99060051416704042460);
>
>     tf(c, y, x) = c*(x+y')-x'';
>
>     real = mem(x) : seq(i, 4,   tf(ba.take(i+1, re_c))
>
>                                 ~ _);
>
>     imaginary = x : seq(i, 4,   tf(ba.take(i+1, im_c))
>
>                                 ~ _);
>
> };
>
>
> process = os.osccos(1000) : analytic;
>
>
> Attached the outputs plotted as coordinates. It is fairly close to a circle, 
> at least with a 1k cosine. Eventually, I'll try to make a comparison between 
> all the designs.
>
> Cheers,
> Dario
>
>
>
> On Sun, 23 Jun 2019 at 23:52, Julius Smith <j...@ccrma.stanford.edu> wrote:
>>
>> > I interpreted your email as if the new fi.ssbf is always "better" than 
>> > hilbert = _ <: H(a1)', H(a2) with ...
>>
>> I did not mean to imply that.  You can use whatever bandpass filter
>> you want, and that choice should of course be adapted to your
>> anticipated input signal(s).  If you know the input is a sinusoid at a
>> known frequency, for example, then you can get by (perfectly) with a
>> quarter-cycle delay at that frequency.  Many people use this
>> approximation for narrowband signals (such as in microwave
>> engineering).
>>
>> I would strongly object to the name "hilbert" as defined, however,
>> because it has two outputs instead of one.
>>
>> - Julius
>>
>> On Sun, Jun 23, 2019 at 2:34 PM Julius Smith <j...@ccrma.stanford.edu> wrote:
>> >
>> > > Agreed, but I was talking about fi.hilbert. Ideally it should turn cos() 
>> > > into sin(), at least according to its name/documentation, not into sin/2.
>> >
>> > I suppose a name change such as "half_hilbert" could be helpful to
>> > avoid confusing "engineering" and "mathematics" definitions of
>> > "hilbert".  However, I cannot think of a good name.
>> > Instead, I suggest we move "hilbert" into a comment in the pospass()
>> > doc (see latest filters.lib).
>> >
>> > As you pointed out earlier, no finite-order filter can be The Hilbert
>> > Transform.  Even being sampled in time makes that impossible.
>> > Therefore, avoiding the name entirely makes good sense.  However, note
>> > that there are few complaints about "Fast Fourier Transform", which is
>> > not the Fourier Transform, and FFTs are similarly (un)scaled according
>> > to engineering principles (avoid gain terms until they are required in
>> > the application).
>> >
>> > - Julius
>> >
>> > On Sun, Jun 23, 2019 at 8:30 AM Oleg Nesterov <o...@redhat.com> wrote:
>> > >
>> > > On 06/22, Julius Smith wrote:
>> > > >
>> > > > Maybe clearer now?  See latest filter.lib.
>> > >
>> > > Thanks, the new doc matches my understanding ;)
>> > >
>> > > > I presently vote against a scaling by 2, but I am open to arguments.
>> > > > Right now, pospass simply passes only positive frequencies, and
>> > > > hilbert is the imaginary part of pospass.  To me this is the simplest
>> > > > view.
>> > >
>> > > Agreed, but I was talking about fi.hilbert. Ideally it should turn cos()
>> > > into sin(), at least according to its name/documentation, not into sin/2.
>> > >
>> > > > None of these filters is ideal.  By considering lowpass, pospass,
>> > > > hilbert, etc., in Faust, you are considering practical filters,
>> > > > nothing ideal.
>> > >
>> > > Of course. But as for fi.hilbert, I simply can't imagine any practical
>> > > usage of it...
>> > >
>> > >
>> > > And in fact there was another reason why I was confused. I interpreted
>> > > your email as if the new fi.ssbf is always "better" than
>> > >
>> > >         hilbert = _ <: H(a1)', H(a2) with {
>> > >                 a1 = 0.6923878, 0.9360654322959, 0.9882295226860 , 
>> > > 0.9987488452737;
>> > >                 a2 = 0.4021921162426, 0.8561710882420, 0.9722909545651, 
>> > > 0.9952884791278;
>> > >                 H_sect(a) = f ~ _ with { f(y, x) = a^2 * (x + y') - x''; 
>> > > };
>> > >                 H(as) = seq(i, outputs(as), H_sect(ba.take(i+1, as)));
>> > >         };
>> > >
>> > > I showed to Dario, at least for frequency shifting. AFAICS, this is not
>> > > necessarily true, this depends. Consider the naive implementations,
>> > >
>> > >         freq_shift_yehar(f) = hilbert  : *(os.oscrc(f)) - *(os.oscrs(f));
>> > >
>> > > and
>> > >
>> > >         freq_shift_ssbf(f) = fi.ssbf(8) : *(os.oscrc(f)) - 
>> > > *(os.oscrs(f));
>> > >
>> > > iiuc the first one will work "better" unless the input frequency is 
>> > > "close"
>> > > to SR/4.
>> > >
>> > > Right?
>> > >
>> > > Oleg.
>> > >
>> > >
>> >
>> >
>> > --
>> >
>> > Julius O. Smith III <j...@ccrma.stanford.edu>
>> > Professor of Music and, by courtesy, Electrical Engineering
>> > CCRMA, Stanford University
>> > http://ccrma.stanford.edu/~jos/
>>
>>
>>
>> --
>>
>> Julius O. Smith III <j...@ccrma.stanford.edu>
>> Professor of Music and, by courtesy, Electrical Engineering
>> CCRMA, Stanford University
>> http://ccrma.stanford.edu/~jos/



-- 

Julius O. Smith III <j...@ccrma.stanford.edu>
Professor of Music and, by courtesy, Electrical Engineering
CCRMA, Stanford University
http://ccrma.stanford.edu/~jos/


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