Hi Klaus and Giuseppe,
A simple and efficient implementation can be done using the min and max
primitives:
limit(lo,hi) = min(hi) : max(lo);
Cheers
Yann
Le lun. 19 juil. 2021 à 11:07, Giuseppe Silvi via Faudiostream-users <
faudiostream-users@lists.sourceforge.net> a écrit :
> Hi Klaus,
>
> import("stdfaust.lib");
>
> minn = hslider("minimum", -6, -10, 0, 0.1);
> maxx = hslider("maximum", +6, 0, 10, 0.1);
>
> // limit
> limit(minn,maxx) = _ <: ba.if( _ < minn, minn , _) <: ba.if( _ > maxx,
> maxx, _);
>
> process = os.osc(1000) : limit(minn,maxx);
> //process = os.osc(1000)*5 : limit(-3,4);
>
> Ciao!
> G
>
>
> > On 19 Jul 2021, at 10:46, Klaus Scheuermann <kla...@posteo.de> wrote:
> >
> > this one is probably simple, but I did not find anything in the syntax
> or libraries.
> >
> > How do I limit a value or signal with a min and a max so it never
> exceeds this range?
> >
> > Something like:
> >
> > min = -3;
> > max = 4;
> > process = _ : limit(min,max) : _
> >
> > I mean, I did try to implement it, but it does not work ;) :
> >
> > // limit
> > limit(x) = ba.if( x < minimum, minimum , x) : ba.if( x > maximum,
> maximum, x) with {
> > minimum = hslider("minimum", -6, -10, 0, 1);
> > maximum = hslider("maximum", +6, 0, 10, 1);
> > };
> > _______________________________________________
> > Faudiostream-users mailing list
> > Faudiostream-users@lists.sourceforge.net
> > https://lists.sourceforge.net/lists/listinfo/faudiostream-users
>
>
>
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