I don't see how the id of a vector has anything to do with its value. The
norm that Miro prints should be the same.

Martin


On 26 May 2014 13:43, Johan Hake <[email protected]> wrote:

> To be honest, I would also assume these two to print the same. But I have
> been bit by the Function::assign-recreate-the-vector behavior quite many
> times now. The point is that the vector in a Function gets recreated after
> an assign.
>
> from dolfin import *
> mesh = UnitSquareMesh(2,2)
> V = FunctionSpace(mesh,"CG",1)
> u0 = Function(V)
> u1 = Function(V)
>
> U = u0.vector()
> print "Same:", U.id()==u0.vector().id()
> u0.assign(u1)
> print "Same:", U.id()==u0.vector().id()
>
> Johan
>
>
> On Mon, May 26, 2014 at 1:32 PM, Martin Sandve Alnæs 
> <[email protected]>wrote:
>
>> Johan, I don't understand what you mean by that. I would also expect
>> these to do the same, i.e. result in an exact copy of ut.vector()?
>>
>> Martin
>>
>>
>> On 26 May 2014 13:27, Johan Hake <[email protected]> wrote:
>>
>>> Function.assign re-create the FOOvector holding the actual values. I
>>> assume this explains the difference in behavior.
>>>
>>> Johan
>>>
>>>
>>>
>>>
>>> On Mon, May 26, 2014 at 1:09 PM, Miroslav Kuchta <[email protected]>wrote:
>>>
>>>> Hi,
>>>>
>>>> please consider the attached snippet. I would assume foo() and bar()
>>>> to do the same thing but that is not the case. Is this a bug in
>>>> Function.assign() or am I missing something about the method's
>>>> behaviour?
>>>> Thanks for answer.
>>>>
>>>> Regards, Miro
>>>> _______________________________________________
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>>>> [email protected]
>>>> http://fenicsproject.org/mailman/listinfo/fenics
>>>>
>>>>
>>>
>>> _______________________________________________
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>>>
>>>
>>
>
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