Am 24.07.2016 um 17:16 schrieb Moritz Barsnick:
On Sun, Jul 24, 2016 at 16:49:30 +0200, Peter White wrote:
<(for f in ./*.MOV; do echo "file '$PWD/$f'"; done)
is a very fancy way of saying *.MOV. ;) Essentially that is what
happens there:
ffmpeg -i *.MOV
No, it isn't at all. It's a bash-ism (or perhaps zdh-ism) which
provides a pseudo file containing the output of the command within the
brackets as content. Valid approach, and it's used in the wiki as well.
https://trac.ffmpeg.org/wiki/Concatenate
Oops, I see that now. Was wondering what that -safe 0 was for. But the
OP still have no -f concat anywhere in their command line. Is it
implied somewhere? Cannot see where, though:
>>> *ffmpeg -safe 0 -analyzeduration 4000000000 -probesize 4000000000
>>> -i <(for f in ./*.MOV; do echo "file '$PWD/$f'"; done) -map 0:0 -map
>>> 0:1 -map 0:2 -c:v copy -c:a copy -map_metadata 0 -copy_unknown
>>> -disposition:a:0 default -disposition:a:1 default OUT.MOV*
But, maybe I am not seeing everything here.
I suppose files.txt is a list of one file path per line? I believe
this is not accepted as input by ffmpeg. It expects media files not
text files listing those.
The original poster is using the concat demuxer ...
At least in their posted command they don't:
>>> *$ ffmpeg -i files.txt -c:v copy -c:a copy OUT.MOV*
No concat demuxer, which is why that files is expected to be a media
file.
You are right though in saying that "files.txt" is being interpreted as
a multimedia file. It either needs the extension .concat (I believe),
or better "-f concat".
-f concat, .concat extension does nothing for me.
Also have a look at what Cley Faye wrote in their reply. To concatenate
files you need the concat filter. Just using "-c:v copy -c:a copy" only
gets you what ffmpeg deems the best quality input.
That's total nonsense. You *cannot* use a filter with "-c copy".
Again, oops. Sorry, I should have known that.
Mark is using the concat *demuxer*, and that may just be fine.
I am not so certain he actually is. ;)
Peter
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