Ill update and continue from there, however it is still not clear from documentation:
Regarding: -vsync vfr From the doc: Frames are passed through with their timestamp or dropped so as to prevent 2 frames from having the same timestamp. This would ensure no repetitions, but does not guarantee that no frames are lost. I want both to be ensured. Further does -vsync have any effect at all if no output framerate is specified? Perhaps the following is interesting ? -frame_drop_threshold parameter Frame drop threshold, which specifies how much behind video frames can be before they are dropped. In frame rate units, so 1.0 is one frame. The default is -1.1. One possible usecase is to avoid framedrops in case of noisy timestamps or to increase frame drop precision in case of exact timestamps. Unfortunately it does not state what the default means nor the option to instruct it to have a truly infinite waiting period. I'm guessing thats what a negative value means, anyone know for sure? I cannot believe that there is no way to tell ffmpeg to extract all frames without repetition or dropping, shouldnt that be the default, and the behaviour I see a bug? 2017-11-04 23:34 GMT+01:00 Carl Eugen Hoyos <[email protected]>: > 2017-11-04 17:45 GMT+01:00 Mikael Persson <[email protected]>: > > The command: > > > > ffmpeg -i somevideo.someformat %07d.png > > Complete, uncut console output missing, please > remember that only current FFmpeg git head is > supported here. > > You may be searching for -vsync vfr > > Carl Eugen > _______________________________________________ > ffmpeg-user mailing list > [email protected] > http://ffmpeg.org/mailman/listinfo/ffmpeg-user > > To unsubscribe, visit link above, or email > [email protected] with subject "unsubscribe". _______________________________________________ ffmpeg-user mailing list [email protected] http://ffmpeg.org/mailman/listinfo/ffmpeg-user To unsubscribe, visit link above, or email [email protected] with subject "unsubscribe".
