> On 22 Nov 2017, at 06:32, Gyan Doshi <gyando...@gmail.com> wrote: > > > > On 11/19/2017 6:09 PM, Bouke / VideoToolShed wrote: > >>> ffmpeg -i HD422.mxf -i 8ch.wav -c:v copy -c:a pcm_s24le -filter_complex \ >>> "[1:a]channelsplit=channel_layout=7.1[a0][a1][a2][a3][a4][a5][a6][a7],\ >>> [a1][0:a:1][a0][0:a:0][0:a:2]amerge=inputs=5[a]" \ >>> -map 0:v -map "[a]" -timecode 01:00:00:00 testmerge01.mxf \ >>> -map "[a2]" -map "[a3]" -map "[a4]" -map "[a5]" -map "[a6]" -map "[a7]" -f >>> null - > >> And after that promote it to 24 bits again. >> Is there a way to force the channel split to work in 24 bits? >> (No idea how to squeeze pcm_s24le into the filter_complex part…) > > The default audio codec for the null muxer is pcm_s16le, and your audio codec > option is only set for the first output, so add '-c:a pcm_s24le' anywhere > after the output mxf filename, and before the pipe character.
Hi Gyan, AH! Stupid me, now I see only the unused channels (that go down the drain) are 16 bits :-) Thanks! Bouke > > Regards, > Gyan > _______________________________________________ > ffmpeg-user mailing list > ffmpeg-user@ffmpeg.org > http://ffmpeg.org/mailman/listinfo/ffmpeg-user > > To unsubscribe, visit link above, or email > ffmpeg-user-requ...@ffmpeg.org with subject "unsubscribe".
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