Hi all, I have a 10-bit 4:2:2 (yuv422p10le) AVI file containing only a video stream:
Input #0, avi, from 'test.avi': Duration: 01:28:00.80, start: 0.000000, bitrate: 221185 kb/s Stream #0:0: Video: v210 (v210 / 0x30313276), yuv422p10le, 720x576, 25 fps, 25 tbr, 25 tbn, 25 tbc The file has a size of 146 GB = 146004770816 bytes. Am I correct to infer that those 10-bit YUV values are grouped into 30-bit packets and encoded into 32-bit/4-byte packets? With 20 bits per pixel (Y + either U or V), that would give a theoretical file size of: 88 * 60 * 25 * 720 * 576 * (10 + 10) / 30 * 32 / 8 = 145981440000 bytes Which seems to more or less match the original file size. Now here's my problem. When I extract the raw video stream: ffmpeg -i test.avi -c:v rawvideo -pix_fmt yuv422p10le -f rawvideo test.raw I get a RAW video file with a size of 96 GB = 96636395520 bytes. I’ve lost one third of the video stream. Another strange thing: if I copy the video stream to another AVI file: ffmpeg -i test.avi -c copy test.copy.avi The resulting file has a size of 64 GB = 64425220302 bytes. This time I’ve lost 56% of the video stream. What's happening here? It seems like I’m missing something obvious. Thanks for any help, Olivier _______________________________________________ ffmpeg-user mailing list ffmpeg-user@ffmpeg.org https://ffmpeg.org/mailman/listinfo/ffmpeg-user To unsubscribe, visit link above, or email ffmpeg-user-requ...@ffmpeg.org with subject "unsubscribe".