Wow! Awesome! сб, 28 янв. 2023 г. в 13:08, Michael Koch <astroelectro...@t-online.de>: > > Hello all, > > this is not a question. This cool equation was designed by Hamid Naderi > Yeganeh. I did only translate it into a FFmpeg command. Let it run and > see what comes out. > > ffmpeg -f lavfi -i color=black:s=hd1080,format=gray -vf > geq=lum='st(0,(X-W/3)/450);st(1,(H/2-Y)/450);255*gt(-7/20-1/PI*atan(175*pow((ld(0)-63/100),2)+3500*pow(abs(ld(1)-1/10),(26/10-6/10*ld(0)))+160*pow(sin(ld(0)+2/5),8)-50*pow(sin(ld(0)+4/5),100)-500)-exp(-2000*(pow((ld(0)-7/4),2)+pow((ld(1)-33/200),2)-1/1000))-exp(1000*(ld(0)-2/5*ld(1)-43/20))+10*(exp(-exp(1000*(-1/4+pow(ld(1)+1/2,2)))-300*(1/10+pow(ld(1),2))*pow((ld(0)-1/2+13/10+(9/100+23*-1/100)*(ld(1)+2/5)+1/10*pow(cos(ld(1)+7/10),20)),2))+exp(-exp(1000*(-1/4+pow(ld(1)+1/2,2)))-300*(1/10+pow(ld(1),2))*pow((ld(0)-2/2+13/10+(9/100+23*1/100)*(ld(1)+2/5)+1/10*pow(cos(ld(1)+7/10),20)),2))+exp(-exp(1000*(-1/4+pow(ld(1)+1/2,2)))-300*(1/10+pow(ld(1),2))*pow((ld(0)-3/2+13/10+(9/100+23*-1/100)*(ld(1)+2/5)+1/10*pow(cos(ld(1)+7/10),20)),2))+exp(-exp(1000*(-1/4+pow(ld(1)+1/2,2)))-300*(1/10+pow(ld(1),2))*pow((ld(0)-4/2+13/10+(9/100+23*1/100)*(ld(1)+2/5)+1/10*pow(cos(ld(1)+7/10),20)),2))),0)' > -frames 1 -y out.png > > You find more mathematical art on his Facebook page: > https://www.facebook.com/HamidNaderiYeganeh > > Michael > > _______________________________________________ > ffmpeg-user mailing list > ffmpeg-user@ffmpeg.org > https://ffmpeg.org/mailman/listinfo/ffmpeg-user > > To unsubscribe, visit link above, or email > ffmpeg-user-requ...@ffmpeg.org with subject "unsubscribe". _______________________________________________ ffmpeg-user mailing list ffmpeg-user@ffmpeg.org https://ffmpeg.org/mailman/listinfo/ffmpeg-user
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