Yes, Ken! Someone else corrected me so it must be true -- I was
wrong! Unfortunately the email was deleted so cannot back check to see
what I missed.
I figure...
Nonetheless there is now a 5/12 within that 5/8 of this larger 12/8
(that you derived from the original metronomic 1/3 slower 4/4) that
remains 1/3 shorter and is subsequently 5/18ths of the original 4/4
but winds up 15/48th of your newly established 12/8. -i.e. an inner
nested triplet and 2/3 within this metronomically accelerated 5/8. Had
it been in 12/12 to 5/12 this would appear as (me logically following
my own argument)- 5/18. In other words all you've done is postpone the
inevitable complication.
So -
Your version:
q=40
4/4
q=qdot
5/8
q=qdot
5/8
q=40 (VERY shorthand)
4/4
Maxima longa!
My version:
q=40
4/4
5/12
5/18
4/4
Longa maxima!
Vis a vis all else- in total -- I too prefer experience over
rationality with my music.
But this was fun!
Jerry
On 9-Jul-05, at 5:20 AM, <[EMAIL PROTECTED]> wrote:
Gerald Berg <[EMAIL PROTECTED]> wrote
But of course this 5/8 is 1/3 longer than the required 5/12. But hey,
who's counting!
Please reread my previous paragraph. The 5/8 (5/Q) relates correctly
to
the duplets (or dotted eighths) in the 12/8 (4/Q. or 8/E.).
Incidentally, this Brit has been happy with whole notes, halves,
quarters etc. for some decades, except when looking for a translation
of maxima and longa.
--
K C Moore
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