Re: ??convection coefficent?? a function of concentration

[Daniel Wheeler]

On May 27, 2006, at 11:37 AM, Damm, Edward F. (E. Buddy) wrote: Jon, I think what you are saying is that I do not have a convection term here at all. My equation is $\frac{\partial u_{c}}{\partial t}=\nabla \left[ D\cdot \nabla u_{c}+u\cdot \nabla \phi \right] $ The last term is a convection term with a coefficient of        $\nabla \phi$ assuming the $u$ is supposed to be a $u_{c}$. OR, $\frac{\partial u_{c}}{\partial t}=\nabla \left[ D\cdot \nabla u_{c}+% \vec{u}\phi \right] $, right? The $u_{c}$ has turned into a vector, it is a scalar isn't it? Or are $u$ and $u_{c}$ different? Daniel Wheeler