On Wed, Jan 18, 2012 at 4:00 PM, Yun Tao <[email protected]> wrote: > Thanks Jon! So I guess as long as I stay under 4th order I'll be fine then.
Hi Yun, The other fourth order Cahn-Hilliard examples seem to work fine, I think the Biharmonic (has no second order term) equation is quite unstable along with the boundary conditions provided. It could also be the choice of solver. That particular example needs to be diagnosed and fixed (we just don't have time), but the fourth order term itself is fine for most of the examples. Cheers -- Daniel Wheeler
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