Sorry for the spam. I just found a quick way to do that: *np.maximum(a,zeros(n))*
where a is a CellVariable and n is the number of cells. This is an element wise comparison of the two arrays. The bigger value of each comparison will be returned. The result is also a CellVariable. I'm emailing in case others have the same problem. On Sun, Feb 2, 2014 at 11:42 AM, yuan wang <[email protected]> wrote: > Dear Fipyers, > > May I know how to quickly assign zero to negative values in a > cellvariable? It could be achieved in the following loop format, but I > think there might be an easier method to do it, which I'm not aware of. > > for j in range(n): > if a.value(j)>0: > a.value(j) =0 > > Thank you. > > Best regards, > Rose > > -- > Yuan (Rose) Wang > PhD Candidate, Tufts University > Cellphone: 617-699-8006 > -- Yuan (Rose) Wang PhD Candidate, Tufts University Cellphone: 617-699-8006
_______________________________________________ fipy mailing list [email protected] http://www.ctcms.nist.gov/fipy [ NIST internal ONLY: https://email.nist.gov/mailman/listinfo/fipy ]
