Dear Admin,
Can you please remove me from the list? I am not using fipy anymore.
Thank you in advance.
On Dec 24, 2014 5:19 PM, "Daniel Wheeler" <[email protected]> wrote:

> On Tue, Dec 23, 2014 at 3:50 PM, Kyle Briton Lawlor
> <[email protected]> wrote:
> > Hi again, Fipy.
> >
> > Suppose that with a solution variable phi (that is a cellVariable), I
> construct a vector field so that there is a vector associated to each point
> on the cell centers of the mesh, is there a way I could compute the
> gradient of that vector field with FiPy?
>
> Hi Kyle,
>
> I think that works, at least this does
>
> In [1]: import fipy as fp
>
> In [2]: m = fp.Grid2D(nx=3, ny=3)
>
> In [4]: v = fp.CellVariable(mesh=m, rank=1)
>
> In [5]: v.shape
> Out[5]: (2, 9)
>
> In [6]: v[0] = m.x
>
> In [7]: v[1] = m.x * m.y
>
> In [10]: print v.getGrad()
> [[[ 0.5   1.    0.5   0.5   1.    0.5   0.5   1.    0.5 ]
>   [ 0.25  0.5   0.25  0.75  1.5   0.75  1.25  2.5   1.25]]
>
>  [[ 0.    0.    0.    0.    0.    0.    0.    0.    0.  ]
>   [ 0.25  0.75  1.25  0.5   1.5   2.5   0.25  0.75  1.25]]]
>
> In [11]: print v.getGrad().shape
> (2, 2, 9)
>
> The first index is the direction, the second index is the direction
> for the gradient operator and the last index is over the cells.
>
> In [12]: print v.getGrad()[0]
> [[ 0.5   1.    0.5   0.5   1.    0.5   0.5   1.    0.5 ]
>  [ 0.25  0.5   0.25  0.75  1.5   0.75  1.25  2.5   1.25]]
>
> In [13]: print v.getGrad()[:,0]
> [[ 0.5  1.   0.5  0.5  1.   0.5  0.5  1.   0.5]
>  [ 0.   0.   0.   0.   0.   0.   0.   0.   0. ]]
>
>
> --
> Daniel Wheeler
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> [email protected]
> http://www.ctcms.nist.gov/fipy
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>
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