Thank you. It works!

Zebo

2015-02-06 7:51 GMT-06:00 Guyer, Jonathan E. Dr. <[email protected]>:

> You should always use fipy.numerix instead of importing numpy directly
> with FiPy. fipy.numerix is a superset of numpy that accommodates FiPy's
> data layout. dot'ing fields of vectors is precisely something that numpy
> doesn't understand, but fipy.numerix does.
>
> See:
>
> -
> http://www.ctcms.nist.gov/fipy/fipy/generated/fipy.tools.html?highlight=numerix#fipy.tools.numerix.dot
> - the "attention" at the top of
> http://www.ctcms.nist.gov/fipy/fipy/generated/fipy.tools.html?highlight=numerix#module-fipy.tools.numerix
> .
> -
> http://www.ctcms.nist.gov/fipy/examples/diffusion/generated/examples.diffusion.anisotropy.html?highlight=dot
>   [note that `numerix.NUMERIX.dot` is identical to `numpy.dot`]
>
>
>
> On Feb 5, 2015, at 1:44 PM, Zebo LI <[email protected]> wrote:
>
> > Here is my problem:
> > The diffusion problem is set up in a Cartesian coordinate system (2D).
> But due to the singularity behavior at the origin point, we need to solve
> the equation in a Polar coordinate system.
> > So I created two meshes in the code: one is the ordinary Grid2D mesh for
> the cartesian system, and the other is a PeriodicTopBottom2D mesh for the
> Polar system (x=ln(r),y=theta. During the calculation we need to do some
> matrix transformation from Cartesian system to the Polar system:
> >
> > M(Polar) = O^{T} *M(Cartesian)*O
> >
> > where
> >
> > O= [(cos(\theta),sin(\theta))\\(-sin(\theta),cos(\theta))].
> >
> > Is there an easy way to realize this operation? Since both O and M
> depend on position, (We expressed  M(Cartesian) and O as functions of r and
> \theta, and wanted to get M(Polar).) the numpy.dot does not works while.
> >
> >
> > best,
> > Zebo
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>
>
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