That worked thanks!

> On 21 Mar 2019, at 18:44, Daniel Wheeler <daniel.wheel...@gmail.com> wrote:
> 
> On Thu, Mar 21, 2019 at 1:14 PM Meier Quintin <quintin.me...@mat.ethz.ch> 
> wrote:
>> 
>> Dear Daniel,
>> Thanks a lot for the help. I got it to work by adding a transientterm().
>> 
>> If I try to use your second trick though:
>> 
>> eq = (DiffusionTerm(coeff=(1.0), var=phi) - numerix.sin(phi) + phi * 
>> numerix.cos(phi)-ImplicitSourceTerm(numerix.cos(phi)) == 
>> TransientTerm(var=phi))
> 
> I think this has the parentheses in the wrong place. Does the code
> that I included in my last email work for you as is?
> 
> This (without the line break)
> ~~~~
> eq = TransientTerm() == DiffusionTerm() - numerix.sin(phi) + phi *
> numerix.cos(phi) - ImplicitSourceTerm(numerix.cos(phi))
> ~~~~
> 
>> I get the error:
>> 
>> ExplicitVariableError: Terms with explicit Variables cannot mix with Terms 
>> with implicit Variables.
> 
> That's because of the parentheses I think.
> 
>> Also, I dont fully understand the expression: I assume the implicit term is 
>> to neutralize the  phi * numerix.cos(phi), so should it not be: 
>> phi*ImplicitSourceTerm(numerix.cos(phi))?
> 
> ImplicitSourceTerm includes the extra variable multiplier
> automatically. It put the source into the matrix diagonal to stabilize
> the solution.
Ok, so adding the ImplicitSourceTerm helps with stability but does not add 
anything relevant to the solution?

> 
>> Also: if I would want a second derivative in time in there to solve the 
>> time-dependent problem, would the best way to do that to define a second 
>> variable:
>> 
>> dphidt=TransientTerm(var=phi)
>> 
>> and solve the coupled equations or is there a different way?
> 
> Yes, right, it can be split into two hyperbolic equations, but FiPy
> doesn't do well with those types of equations. It doesn't have the
> correct numerical schemes. I think CLAWPACK might be a better bet for
> that.
Ok, no problem, I was just interested, its not that important for me :)

> 
> -- 
> Daniel Wheeler
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