>> select 1.000000000 / 1.0000000000 from rdb$database

DY> I suppose this particular case (and maybe some others of the same kind)
DY> can be worked around. Perhaps we could truncate intermediate results to
DY> fit the maximum supported bitness if and only if the trailing bytes are
DY> insignificant zeroes.

DY> But I really doubt this would be enough as a generic solution.

Agreed. It may help in some cases, but will not help in the case where
all members of the equation are fields or variables.

[]s
Carlos
http://www.firebirdnews.org
FireBase - http://www.FireBase.com.br


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