I had finally figured it out just before your reply
SELECT DISTINCT P.SOC_SEC_NO,
(SELECT COUNT(*)
FROM PERSON P2
WHERE P2.SOC_SEC_NO = P.SOC_SEC_NO) AS CNT
FROM PERSON P
WHERE P.SOC_SEC_NO IS NOT NULL
GROUP BY 1
HAVING (SELECT COUNT(*)
FROM PERSON P3
WHERE P3.SOC_SEC_NO = P.SOC_SEC_NO) > 1
This appears to work. See anything that I should change?
-----Original Message-----
From: [email protected]
[mailto:[email protected]]
Sent: Thursday, February 04, 2016 1:25 PM
To: [email protected]
Subject: Re: [firebird-support] How do find duplicates in a table?
04.02.2016 20:09, 'stwizard' [email protected] [firebird-support] wrote:
> How do I form a SQL Select statement that will return which records in
> my PERSON table have duplicate SOC_SEC_NO.
RTFM GROUP BY, HAVING, COUNT().
--
WBR, SD.
