Just to be clear, all of these approaches detect the firebug
"console". If the user disables the console, we do not want Firebug to
be detectable.
jjb
On Sep 22, 8:12 am, croberson <[EMAIL PROTECTED]> wrote:
> I use this:
>
> if (typeof window.loadFirebugConsole == "undefined") {
>
> }
>
> because before the window is loaded, window.console is undefined
>
> On Aug 15, 2:01 pm, Soichi Hayashi <[EMAIL PROTECTED]> wrote:
>
> > I'd rather not put that if statement on every single lines where I use
> > console.log..
>
> > I guess I am looking for something like..
>
> > if(!window.console) {
> > var console = {
> > log: function(foo) {//do nothing};
> > dir: function(foo) {//do nothing};
> > };
>
> > }
>
> > But I am pretty sure that somebody else has come up with more elegant
> > solution.. I just don't want to reinvent the wheel..
>
> > Thanks,
> > Soichi
>
> > John J Barton wrote:
> > > Why not
> > > if (window.console) console.log("starting logging");
>
> > > jjb
>
> > > On Aug 15, 8:19 am, Soichi Hayashi <[EMAIL PROTECTED]> wrote:
>
> > >> Hi.
>
> > >> Is there a way to detect that the browser doesn't have firebug installed
> > >> so that "console.log()" will be ignored instead of causing the page to
> > >> crash?
>
> > >> Thanks,
> > >> Soichi
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