If I understand correctly,
then you can't really do this. The PHP is interpreted on the server,
and the browser (and firebug) just get the results - it knows nothing
about PHP, plus the line numbers will be different.
I would just echo some debugging statements in your PHP - perhaps some
HTML comments, or some javascript statements that don't change
behavior. (myself, I just do something like echo "<script>
window.debug_info += '{$debug_message}'; </script>";)
There's something called FirePHP - I'm not sure what it does, but it
might be worth looking into.
Just my 2 cents.
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