The original source isn't the same that what's shown on the screen, so
using that would make Firebug absolutely useless to debug any dynamic
page.

On 7 jun, 08:38, Falconer <[email protected]> wrote:
> Okay, makes sense. However... wouldn't it be more logical for Firebug
> to read the source of the document then, instead of what Firefox is
> showing it? (I can understand that this may be somewhat more complex).
>
> On Jun 6, 12:26 pm, alfonsoml <[email protected]> wrote:
>
> > It's Firefox the one that reports your content that way.
> > For example load one of your pages (without Firebug enabled) and run
> > this in the location bar:
> > javascript:alert(document.body.innerHTML)
>
> > You'll see that all that "clutter" is already there, so Firebug will
> > have a hard time telling apart what's due to Firefox and what's your
> > original code.
>
> > On 6 jun, 18:55, Falconer <[email protected]> wrote:
>
> > > Hi all,
>
> > > Before continuing, I would like to say thanks to the creators of
> > > FireBug. It's a fantastic tool and I do not ever want to be without it
> > > anymore.
>
> > > There is one thing that is bugging me more and more though, and that
> > > is the crappy code that shows up in firebug that is not part of my
> > > original code. I'm talking about the "moz" stuff and numerous
> > > 'transparent' insertions whenever I set a background in CSS and a ton
> > > of other things.
>
> > > It's just clutter and does nothing to help me. It would be great if
> > > this could be left out and Firebug just takes the code as if you are
> > > doing a view-source. If (I can't see why) this is useful to some
> > > people, I suggest adding a tickbox somewhere that lets the user chose.
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