It works in Firebug 1.5a6, so it should work in Firebug 1.4b3, http://getfirebug.com/releases jjb
On Jun 27, 10:57 am, rhill <[email protected]> wrote: > I am using Firefox 3.0.11, and Firebug 1.3.3. > > There is a particular function which contain the following line: > > ... > while (nExecuteSteps-- && this.pq.length()>0) { > ve=this.pq.pop(); <<<<<< starting here, Firebug *doesn't see* > this > as valid code > ... > > All the code below this line in this particular function is not seen > as valid code by Firebug -- hence if I set a breakpoint in there it is > seen as "undefined", can't debug :-(. However, if I change the above > line with: > > ... > for (; nExecuteSteps>0 && this.pq.length()>0; nExecuteSteps--) { > ve=this.pq.pop(); <<<<<< starting here, Firebug *sees* this > as valid > code > ... > > Firebug correctly sees all the line below as valid code (therefore I > can now set a breakpoint). > > I have no idea why the former causes problem to Firebug. > > Test case is at: > > http://www.raymondhill.net/voronoi/firebug-test.php > > The problem is at line 841 > ofhttp://www.raymondhill.net/voronoi/firebug-test.js. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Firebug" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/firebug?hl=en -~----------~----~----~----~------~----~------~--~---
