On Aug 19, 1:16 pm, Olivier Cornu <[email protected]> wrote:
> >>> Also, i suppose "this" should be the Sandbox in order to see things as
> >>> the debugged script does.
>
> >> I don't know whether or not the sandbox should be "this", since the
> >> whole sandbox model makes not sense to me. I never could figure out
> >> what it did which is why we took it out of Firebug.
>
> As i've found out, "this" refers to the script scope. It usually is a
> Window but in case of a sandboxed script it's a Sandbox. It's fine
> like that.
> For the sake of completion: the empty "this" issue was because the
> Sandbox object has no hasOwnProperty(), __lookupGetter___() and
> __lookupSetter__() methods -- dom.js needs them to correctly print the
> object hierarchy. If i put dummy implementations of these methods
> everything works fine. :-)
Ok, more evidence that the Sandbox is half-baked ;-)
>
> Also, very interestingly: "As of Firefox 3.5/Gecko 1.9.1, it's
> possible to optionally specify the JS version, filename, and line
> number of the code being evaluated" [1].
> This means it seems possible for the Firebug-1.5 to support sandboxed
> scripts debugging (when they provide such information) without too
> many changes: they pretty much look like other top-level scripts. The
> only thing needed is a way for getFrameScopeWindowAncestor() to
> discover which window the script should be attached to (if any).
> The most generic test i've found (also working with GM) is the
> following: if the sandbox prototype is a Window (or a XPCNW of a
> Window) return it, otherwise the sandboxed script is ignored. It
> probably makes sense to debug sandboxed scripts which are as tied to a
> Window as that, although it's not a perfect test to filter relevant
> sandboxed scripts...
But that assumes a specific model for how the sandbox is used. On the
other hand, as far as I know GM is the only user of the sandbox, so
why not.
jjb
>
> --
> Olivier
>
> [1]https://developer.mozilla.org/en/Components.utils.evalInSandbox
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