Please try Firebug 1.5b5, http://getfirebug.com/releases/firebug/1.5X. If you still have a problem, post a complete test case to http://code.google.com/p/fbug/issues/list and I'll fix it.
jjb On Dec 4, 11:49 pm, Patrick <[email protected]> wrote: > I got the latest version of Firebug and installed in on Firefox 3.5.5 > browser. > > I have a Javascript file which shows up as an enabled script so long > as I don't have the following function in the script file. > > function onChangeUnitsOfLength() { > var hUnits = getElementsById("hUnits"); > var m = getElementById("m"); > var in = getElementById("in"); > var ft = getElementById("ft"); > > switch(hUnits.value) { > case 0: > m.style.zIndex= "-1"; > in.style.zIndex="0"; > ft.style.display="inline"; > break; > case 1: > m.style.zIndex="-1"; > ft.style.display="none"; > in.style.zIndex="0"; > break; > case 2: > m.style.zIndex="0"; > ft.style.display="none"; > in.style.zIndex="-1"; > break; > default: > }; > > }; > > When I add this function to the file, my file no longer shows in the > drop down menu and there is no code where I can set breakpoints. I > don't think an error in the code should break the debugger but it > does. It would be nice if there were some way to spot errors in the > code before you try to evaluate it. -- You received this message because you are subscribed to the Google Groups "Firebug" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/firebug?hl=en.
