Thanks John!! I will use option #3. Jim On Aug 6, 5:37 pm, John J Barton <[email protected]> wrote: > On Aug 6, 10:55 am, JimO <[email protected]> wrote: > > > > > > > Hi All, > > > I am a brand new member to this group; also, very new to Firebug and > > jQuery. > > > In attempting to learn Firebug and jQuery (AT THE SAME TIME) I ran one > > of the first examples in jQuery Cookbook (by O'Reilly.) It is on page > > 4 and does a simple hide(), text(), addClass(), and show(). The > > program changes the text value "old content" to "new content". > > > The problem I am having is that instead of getting the expected result > > of: > > > new content > > > (in the upper left-hand corner of the browser window, I am getting: > > > new content > > new content. > > > The program in question works fine in Safari and in Firefox when > > Firebug is NOT enabled. > > > After a little research, I discovered that there is a <div> with an ID > > of _firebugConsole. I notice that when the addClass() function is > > performed this <div> then has an ID and CLASS of > > "#_firebugConsole.updatedContent". > > The div _firebugConsole is added by Firebug 1.5 to support the Console > operations. > > > > > When the jQuery('div').text('new content') statement is performed it > > is insert this text into this <div>. > > > I thought that the problem might be that I did not have FireQuery > > installed, however, the problem occurs even after I installed it. > > > Has anybody else experienced this problem?? Does anybody have a > > solution?? > > 1. disable the Firebug Console, OR > 2. use Firebug 1.6, OR > 3. Write your jQuery code relative to nodes you know are part of your > application, eg nodes you obtain by getElementById or > getElementsByClassName. > > I suggest #2 and #3. > > jjb > > > > > > > Thanks, > > > Jim
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