[This message was posted by douglas young of RTTT <[email protected]> to the "FAST Protocol" discussion forum at http://fixprotocol.org/discuss/46. You can reply to it on-line at http://fixprotocol.org/discuss/read/d2f57ce9 - PLEASE DO NOT REPLY BY MAIL.]
I try to encode a message and it keep give the error. The problem is came from "constant" in side of a "sequence". (146 is sequence length, 55 and 8 are constant in side of sequence) "Error occurred on line #1: Parsed 3 groups in sequence when 1 were expected. [line: 1128=8 35=R 49=CME 34=3 146=1 55=[N/A] 38=100 22=8]: Parsed 3 groups in sequence when 1 were expected." Message give error: 1128=8 35=R 49=CME 34=3 146=1 55=[N/A] 38=100 22=8 Message ok: 1128=8 35=R 49=CME 34=3 146=1 38=100 http://www.fixprotocol.org/ns/fast/td/1.1";> [You can unsubscribe from this discussion group by sending a message to mailto:[email protected]] --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Financial Information eXchange" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/FIX-Protocol?hl=en -~----------~----~----~----~------~----~------~--~---
