Hi there,
Try this
a = [2,1,5,1,3];
var l:Number = a.length;
var i:Number = -1;
var b:Array = [];
var sum:Number = 0;
while (++i < l) {
sum += a[i];
trace(sum);
var tmp:Array = [];
var n:Number = a[i];
while (--n >= 0) {
tmp [n] = sum;
}
b = b.concat(tmp);
}
trace(b);
Regards,
Dimitrios Bendilas
----- Original Message -----
From: "Merrill, Jason" <[EMAIL PROTECTED]>
To: "Flashcoders mailing list" <[email protected]>
Sent: Thursday, January 19, 2006 10:01 PM
Subject: [Flashcoders] expanding a second array given values of the
firstarray
Should be pretty straightforward, but I am having trouble wrapping my
head around it. I want to create an array of N length, which is expanded
according to the values of another array. What I mean is, for example:
taskSet = [2,1,5,1,3] //values of how much the new array should expand
I want to, based on the values of the taskSet array, make a running
add-up total of the values of taskSet & repeat that number in the final
array taskSet[n] times in the new taskSetExpanded array. I do not mean
just add up the values of taskSet which I already know how to do (though
by so doing, I know that also shows the length of the final array).
So (and this may be the easiest way to explain) given the array:
taskSet = [2,1,5,1,3];
The taskSetExapanded array would then become an array with these exact
values:
[2,2,3,8,8,8,8,8,9,12,12,12]
...where for example, the number 8 as seen in the array(8 comes from the
running total of 2+1+5 from TaskSet) is repeated 5 times (where 5 is the
value of taskSet[3])
..and where for example the number 9 as seen in the array (9 comes from
the running total of 2+1+5+1 from TaskSet) is repeated 1 time (where 1
is the value of taskSet[4])
Etc.
Make sense? Perhaps I over explained. I have tried numerous for loops
and never been able to get the final result I need. Any help is
appreciated. Thanks!
Jason Merrill | E-Learning Solutions | icfconsulting.com
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