Merrill, Jason wrote:
while (--i -(-1)) {
Jason, very interesting way of counting through the array. I haven't
see this approach before. Are there any benefits to using (--i -(-i))
in the expression over something like the following?:
while (i--) {
It seems like your loop would need to do two calculations each trip.
One for decrementing i and the second for adding 1 to it to keep the
number above zero so it returns true. If you decrement i after the
condition using i-- instead of before the condition with --i you won't
need add 1 to it. Just an idea.
However, as far as I know you're right looping through the array in AS
2.0 is the only way to find the index of an item. You might also want
to use === instead of == to do strict comparing so "12" doesn't equal
12. Depends on what you need tho.
One thing I might add to your function is the ability to return -1
instead of undefined when an item isn't found which is more consistent
with the String.indexOf method.
Thankfully, in AS 3.0 there is a method to find the index and as fate
would have it it's called indexOf(). It returns either the index if
found or -1 if not found. You would use it like:
var idx:Number = a.indexOf("d");
Cheers,
-- James
James O'Reilly
www.jamesor.com
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