Check your algebra, Since sin(a) = y/r, then y = r sin(a), etc.
P. >> -----Original Message----- >> From: [EMAIL PROTECTED] [mailto:flashcoders- >> [EMAIL PROTECTED] On Behalf Of Jayson K Hanes >> Sent: Sunday, October 22, 2006 7:42 PM >> To: Flashcoders mailing list >> Subject: RE: [Flashcoders] Q:Elementary Trig part 2 >> >> Been awhile since I've explained this to anyone.. lets see how this >> goes! >> >> "SOHCAHTOA" (so-ca-toa) >> >> Sin(a) = opposite/hypotenuse >> Cos(a) = adjacent/hypotenuse >> Tan(a) = opposite/adjacent >> >> a = angle in RADIANS *not* degrees.. you'll have to convert degrees to >> radians with knowing: >> >> ..there are PI (3.14159..) radians in 180 degrees (a fundamental), thus: >> a = A*(PI/180), thus: >> a = 45*(3.14159/180) = .785 (roughly) >> >> Given r and angle=A degrees converted to a radians, r is the same as the >> length of a basic triangles' hypotenuse in this -- we're looking for x,y >> .. moving on: >> >> A=45 degrees but converted to a=.785 radians (approx).. we know that: >> >> r=10, and should know that: >> r=sqrt(x^2+y^2) (per Pythagoras theorem) >> >> so we're going to reverse format the SOH and CAH parts since we know the >> length of the hypotenuse and need to find out x and y (the opposite and >> adjacent sides' lengths) one at a time based on angle, a in radians: >> >> sin(a)=y/r, and, >> cos(a)=x/r, which translates to: >> >> y=sin(a)/r, and >> x=cos(a)/r, however: >> >> y=sin(a)/10, and >> x=cos(a)/10, thus: >> >> y=sin(.785)/10, and >> x=cos(.785)/10, thus: >> >> y=0.707/10 = 7.07 (roughly) >> x=0.707/10 = 7.07 (roughly) >> >> I think that should set you on you on track! Hope that helps :) >> >> -Jayson >> >> > -----Original Message----- >> > From: [EMAIL PROTECTED] [mailto:flashcoders- >> > [EMAIL PROTECTED] On Behalf Of [EMAIL PROTECTED] >> > Sent: Sunday, October 22, 2006 3:11 PM >> > To: [email protected] >> > Subject: [Flashcoders] Q:Elementary Trig part 2 >> > >> > Another way of stating my problem: >> > >> > >> > Given an initial angle, and a circle with radius r, how do you >> determine >> > the x,y coordinates of the point p1 on the circumference of this >> > circle...assuming the circle's center is at 0,0.? >> > >> > >> > >> > [e] jbach at bitstream.ca >> > [c] 416.668.0034 >> > [w] www.bitstream.ca >> _______________________________________________ >> [email protected] >> To change your subscription options or search the archive: >> http://chattyfig.figleaf.com/mailman/listinfo/flashcoders >> >> Brought to you by Fig Leaf Software >> Premier Authorized Adobe Consulting and Training >> http://www.figleaf.com >> http://training.figleaf.com _______________________________________________ [email protected] To change your subscription options or search the archive: http://chattyfig.figleaf.com/mailman/listinfo/flashcoders Brought to you by Fig Leaf Software Premier Authorized Adobe Consulting and Training http://www.figleaf.com http://training.figleaf.com
