Why not throw another option in the mix :)
I think this one is more efficient because it only loops through the
number array once at the beginning... but I'm not an optimization
expert.
// define your array of "bad" numbers
var nList_array:Array = new Array(12, 34, 21, 46, 52)
// create an object with a boolean value for each "bad" number
var nList_object:Object = new Object();
for (var i:Number = 0; i<nList_array.length; i++){
var num:Number = nList_array[i];
nList_object["bad"+num] = false;
}
// create a function to "test" a number;
function testNumber(num:Number):Boolean
{
if (nList_object["bad"+num] === false){
return false;
} else {
return true;
}
}
// Now test it
for (var i:Number = 0; i<100; i++){
if (testNumber(i)){
trace("doing something with "+i);
} else {
trace("BAD NUMBER: "+i);
}
}
On Dec 20, 2006, at 4:42 PM, Eduardo Barbosa wrote:
Hi all,
given a list of numbers such as: (12, 34, 21, 46, 52 ... )
what would be the best way to achieve this:
a++;
if ( a != 12 && a != 34 && a != 21 && a != 46 && a != 52 ... ) {
// do something
}
Am doing my research and trying out some solutions but i thought
that in the
meantime someone may have a quick ready answer for this or some
good hints.
thanks a lot!
Eduardo
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