Hi Michael,
how about the following (not tested):
var petsList:XMLList = pets.*;
var sugarDaddy:XMLList = petsList.(pet name == "Sugar");
trace(sugarDaddy@group);
HTH
Willem van den Goorbergh

On 5 mei 2011, at 17:32, Mendelsohn, Michael wrote:

> Hi list...
> 
> I'm trying to find some xml's parent attribute.
> 
> I have <pet name="Sugar"/> and I want to find "B".
> 
> var pets:XML = <pets group="A">
>       <pet name="Rover"/>
>       <pet name="Buffy"/>
> </pets>
> <pets group="B">
>       <pet name="Spot"/>
>       <pet name="Sugar"/>
> </pets>;
> 
> I can't seem to find it.  Anyone know how?
> 
> Thanks,
> - Michael M.
> 
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Geografiek is a Dutch, Utrecht-based map and chart design company.
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