Like so?
taskSet = [2,1,5,1,3];
taskSetExpanded = new Array();
for(var i=0, len=taskSet.length; i<len; i++){
for(j=0; j<taskSet[i]; j++){
if(!j){
var res = 0;
for(k=0; k<=i; k++){
res += taskSet[k];
}
}
taskSetExpanded.push(res);
}
}
trace(taskSetExpanded);
// output: 2,2,3,8,8,8,8,8,9,12,12,12
hth
--------------
Andreas Weber
motiondraw.com
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Merrill,
Jason
Sent: Donnerstag, 19. Januar 2006 21:02
To: Flashcoders mailing list
Subject: [Flashcoders] expanding a second array given values of the
firstarray
Should be pretty straightforward, but I am having trouble wrapping my
head around it. I want to create an array of N length, which is expanded
according to the values of another array. What I mean is, for example:
taskSet = [2,1,5,1,3] //values of how much the new array should expand
I want to, based on the values of the taskSet array, make a running
add-up total of the values of taskSet & repeat that number in the final
array taskSet[n] times in the new taskSetExpanded array. I do not mean
just add up the values of taskSet which I already know how to do (though
by so doing, I know that also shows the length of the final array).
So (and this may be the easiest way to explain) given the array:
taskSet = [2,1,5,1,3];
The taskSetExapanded array would then become an array with these exact
values:
[2,2,3,8,8,8,8,8,9,12,12,12]
...where for example, the number 8 as seen in the array(8 comes from the
running total of 2+1+5 from TaskSet) is repeated 5 times (where 5 is the
value of taskSet[3])
..and where for example the number 9 as seen in the array (9 comes from
the running total of 2+1+5+1 from TaskSet) is repeated 1 time (where 1
is the value of taskSet[4])
Etc.
Make sense? Perhaps I over explained. I have tried numerous for loops
and never been able to get the final result I need. Any help is
appreciated. Thanks!
Jason Merrill | E-Learning Solutions | icfconsulting.com
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