Hi Derek,

Thanks for your thoughts.  My situation is that I have two Trees that are
populated by the same XML data.  What I would like to do is :

When the user selects a node on Tree1, the same node in Tree2 is selected.

How would one do this do you think.

Tim

On 1/23/06, Derek Vadneau <[EMAIL PROTECTED]> wrote:
>
> You are getting the display index and then trying to get a node based on
> that index.  That won't work like you expect.
>
> The display index refers to the nodes position VISUALLY in the tree.  This
> may have nothing to do with the nodes' position in the XML.
>
> If you have this in a tree:
> Folder 1 (open branch)
> - Item 1 (leaf)
> - Item 2 (leaf)
> Folder 2 (closed branch)
> Folder 3 (open branch)
> - Item 1 (leaf)
> - Item 2 (leaf)
>
> The display index of the Folder 3 > Item 1 node is 5.  Yet if you tried to
> get the node at 5 (i.e. tree.getTreeNodeAt(5)) it would return undefined,
> since there is no node at index 5 of the tree.
>
> When you say tree.getTreeNodeAt(index), the index refers to the childNodes
> array of the tree.
>
> Does that help?
>
>
> Derek Vadneau
>
> ----- Original Message -----
> From: "Tien Nguyen" <[EMAIL PROTECTED]>
> To: <[email protected]>
> Sent: Monday, January 23, 2006 3:19 PM
> Subject: SPAM-LOW: [Flashcoders] Flash8 Tree Gurus
>
>
> Hi All,
>
> I've been working with Flash8 Tree and have the following situation:
>
>         var treeIndex:Number = layoutTree.getDisplayIndex(
> layoutTree.selectedNode);
>         trace("SelectedTreeIndex = " + treeIndex);
>
>         trace("TreeChanged = " + layoutTree.selectedNode );
>         trace("TreeNode = " + layoutTree.getTreeNodeAt(treeIndex));
>
> The problem is that the TreeNode value from the trace is "Undefined".
>
> Oddity:  When the treeIndex value is 0, then the TreeNode value is the
> correct XML of the entire tree.
>
> I am working with ARP architecture.  What would the problem be in this
> case.
>
> Sincerely
>
> Tim
>
>
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