I forget you can use "Array.NUMERIC" when you want to sort an array :D
So you must to put:
aMovieClipsSorted.sort(Array.NUMERIC);
Erik Porroa V. escribió:
Ey Stephen, you can do something like this:
//Create a function that return the sorted numbers
function sortByNumber(a, b) {
return (a > b);
}
//I guess this array will be generated dinamically
var aMovieClips:Array = new Array("mcClip0", "mcClip1", "mcClip2");
//A new array where will go the scaled numbers
var aMovieClipsSorted:Array = new Array();
//A loop that put all the xScales in the new Array
for(var j:Number = 0; j<aMovieClips.length; j++){
aMovieClipsSorted.push(Number(Math.round(_root["mcClip"+j]._xscale)));
}
//Testing
trace(aMovieClipsSorted)
aMovieClipsSorted.sort(sortByNumber);
trace(aMovieClipsSorted)
And that's all, I put a Math.round method that return a rounded number
(you can change it for his original xScale)
Cheers!
Erik
http://www.porroa.com/erik
Hello All. Here is what I have and what I'm trying to do:
I have an array that contains 3 objects (which are all movie clips),
like so:
var myArray:Array = ["mcClip1", "mcClip2", "mcClip3"];
I want to sort this array according to the _xscale of these clips.
Does anyone know how I can do this.
This is my line of thought, which I know is wrong, but might give
more insight:
myArray._xscale.sort(Array.DESCENDING);
Please advise if you can.
Thanks,
Stephen.
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