Been awhile since I've explained this to anyone.. lets see how this goes! "SOHCAHTOA" (so-ca-toa)
Sin(a) = opposite/hypotenuse Cos(a) = adjacent/hypotenuse Tan(a) = opposite/adjacent a = angle in RADIANS *not* degrees.. you'll have to convert degrees to radians with knowing: ..there are PI (3.14159..) radians in 180 degrees (a fundamental), thus: a = A*(PI/180), thus: a = 45*(3.14159/180) = .785 (roughly) Given r and angle=A degrees converted to a radians, r is the same as the length of a basic triangles' hypotenuse in this -- we're looking for x,y .. moving on: A=45 degrees but converted to a=.785 radians (approx).. we know that: r=10, and should know that: r=sqrt(x^2+y^2) (per Pythagoras theorem) so we're going to reverse format the SOH and CAH parts since we know the length of the hypotenuse and need to find out x and y (the opposite and adjacent sides' lengths) one at a time based on angle, a in radians: sin(a)=y/r, and, cos(a)=x/r, which translates to: y=sin(a)/r, and x=cos(a)/r, however: y=sin(a)/10, and x=cos(a)/10, thus: y=sin(.785)/10, and x=cos(.785)/10, thus: y=0.707/10 = 7.07 (roughly) x=0.707/10 = 7.07 (roughly) I think that should set you on you on track! Hope that helps :) -Jayson > -----Original Message----- > From: [EMAIL PROTECTED] [mailto:flashcoders- > [EMAIL PROTECTED] On Behalf Of [EMAIL PROTECTED] > Sent: Sunday, October 22, 2006 3:11 PM > To: flashcoders@chattyfig.figleaf.com > Subject: [Flashcoders] Q:Elementary Trig part 2 > > Another way of stating my problem: > > > Given an initial angle, and a circle with radius r, how do you determine > the x,y coordinates of the point p1 on the circumference of this > circle...assuming the circle's center is at 0,0.? > > > > [e] jbach at bitstream.ca > [c] 416.668.0034 > [w] www.bitstream.ca _______________________________________________ Flashcoders@chattyfig.figleaf.com To change your subscription options or search the archive: http://chattyfig.figleaf.com/mailman/listinfo/flashcoders Brought to you by Fig Leaf Software Premier Authorized Adobe Consulting and Training http://www.figleaf.com http://training.figleaf.com
