Wouldn't doing the splice there change the indexes of everything else
in the array and mess up the loop?
For instance:
[1, 2, A, A, 5, A, 7]
say you're deleting the As.
The first time you do a splice you remove the first one, and get:
[1, 2, A, 5, A, 7]
The index of everything after the first A has now changed. The second
one is now at index 3, but you already handled index 3 in the for
loop. Is the for-in loop smart enough to run index 3 again, since the
value there is new?
-Andy
On 12/21/06, T. Michael Keesey <[EMAIL PROTECTED]> wrote:
Quite simple:
for (var key:String in myArray1) {
if (myArray1[key][1] < 0) {
myArray1.splice(Number(key), 1);
}
}
BTW, "myArray1" is not a great name for a variable ... why not
"scoreRecords" or "scores" or something? Also, storing different types
of data in an array is a recipe for confusions. The element arrays
would be better as objects, e.g.: {name: "A", score: -1}.Then the code
would be more readable:
for (var key:String in scoreRecords) {
var record:Object = scoreRecords[key];
if (record.score < 0) {
scoreRecords.splice(Number(key), 1);
}
}
Or the whole thing could just be an associative array (i.e., hash object):
var scores:Object = {A: -1, B: -1, C: 0};
// ...
for (var key:String in scoreRecords) {
if (scoreRecords[key] < 0) {
delete scoreRecords[key];
}
}
On 12/21/06, Mike Cobb <[EMAIL PROTECTED]> wrote:
> -
>
> Hi everyone,
>
> I'm having a braindead moment today, which I was hoping someone could
> help me with.
>
> I have the following array...
>
> //Create array with 5 elements
> var myArray1:Array = new Array();
> myArray1.push( new Array("A:", -1) );
> myArray1.push( new Array("B:", -1) );
> myArray1.push( new Array("C:", 0) );
> myArray1.push( new Array("D:", 0) );
> myArray1.push( new Array("E:", -1) );
> myArray1.push( new Array("F:", 1) );
> myArray1.push( new Array("G:", 0) );
> myArray1.push( new Array("H:", -1) );
> //name, score
>
> ...and I'm trying to remove all the elements in myArray1 with a score of
> less than 0 without sorting/reordering the array at all.
>
> I was trying to use a 'for loop', but obviously as the elements are
> removed, the length of the array changes & causes the wrong elements to
> be deleted.
>
> Can anyone help?
>
> Thanks,
> <Mike>
>
> --
> -------------------------------------
> Mike Cobb
> Creative Director
> HMC Interactive
> -------------------------------------
> Tel: + 44 (0)845 20 11 462
> Mob: + 44 (0)785 52 54 743
> Web: http://www.hmcinteractive.co.uk
> -------------------------------------
> Grosvenor House, Belgrave Lane,
> Plymouth, PL4 7DA, UK.
> -------------------------------------
>
> I've got a new e-mail address: [EMAIL PROTECTED]
> Please update your address book. Thanks.
>
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--
T. Michael Keesey
Director of Technology
Exopolis, Inc.
2894 Rowena Avenue Ste. B
Los Angeles, California 90039
--
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