Hi, thanks for your reply! My curve isn't exactly a circle. Here's what my animated curve would look like: http://pages.videotron.com/poubou/flash/cannes01.html
The curve is drawn using the drawing API: example: mc.moveTo(0,0); mc.curveTo(400,900,0,800); So, I know the 3 bezier points that define my curve: startpoint = 0,0 middlepoint = 400,900 endpoint = 800,0 With those values in hand, how can I apply them to your function: > f(x) = A*x + x^2 Do I make any sense? On 4/25/07 3:50 PM, "Jobe Makar" <[EMAIL PROTECTED]> wrote: > Hi, > > Your typical funciton looks something like this in math books: > > f(x) = A*x + x^2 //just an example > > Where f(x) is essentially 'y'. So, you just need the equation that defines > your curve. The curve in your jpg appears to be a circle. > > y = sqrt(x^2 + r^2) //where r is the radius > > That actually yields + or - and you just pick what fits your situation best. > So, you pump in an x and get you 2 y's. Pick the best y and use it. _______________________________________________ Flashcoders@chattyfig.figleaf.com To change your subscription options or search the archive: http://chattyfig.figleaf.com/mailman/listinfo/flashcoders Brought to you by Fig Leaf Software Premier Authorized Adobe Consulting and Training http://www.figleaf.com http://training.figleaf.com
