yeh - i started trying to do that but just got myself into a moody
bluddle - i'll prolly go back and try to rewrite it a bit cleaner
when i'm happy i'll hit deadline
here's what i ended up with -
var myTempArray:Array = [];
designerArray.sort();
for (var i:Number = 0; i < designerArray.length; i++) {
if (designerArray[i] != designerArray[i-1]) {
myTempArray.push(designerArray.slice(i,i+1));
}
}
designerArray = myTempArray;
thanks for the tips guys
On 22 May 2007, at 18:13, Rákos Attila wrote:
Don't you think that you should take into consideration that the
length of the array can change during the loop?
Attila
ABER> //loop through items, removing any sitting next to a duplicate
ABER> for (var i:Number = 0; i < myArray.length; i++) {
ABER> if (myArray[i] == myArray[i+1]) {
ABER> myArray.splice (i, 1);
ABER> }
ABER> }
_______________________________________________
Flashcoders@chattyfig.figleaf.com
To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Brought to you by Fig Leaf Software
Premier Authorized Adobe Consulting and Training
http://www.figleaf.com
http://training.figleaf.com
_______________________________________________
Flashcoders@chattyfig.figleaf.com
To change your subscription options or search the archive:
http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
Brought to you by Fig Leaf Software
Premier Authorized Adobe Consulting and Training
http://www.figleaf.com
http://training.figleaf.com
