var lines : Array = (str.indexOf( "\r\n" ) > -1) ? str.split( "\r\n" )
: str.split( "\n" );
Or, if you want to take MacOS 9 into account:
var lines : Array;
if( str.indexOf( "\r\n" ) > -1 ) {
lines = str.indexOf( "\r\n" );
} else if( str.indexOf( "\n" ) > -1 ) {
lines = str.split( "\n" );
} else if( str.indexOf( "\r" ) > -1 ) {
lines = str.split( "\r" );
} else {
lines = str;
}
(You don't actually need the "default", splitting on a non-existing
string should return an array of length 1. It's just more clear that
way.)
HTH,
Mark
On 9/12/07, Danny Kodicek <[EMAIL PROTECTED]> wrote:
> I'm looking for a simple, reliable method for splitting a string into its
> constituent lines (at the hard line breaks - this isn't a text wrapping
> thing). The problem is that line breaks could be Chr(10) or Chr(13), or
> indeed both. I've done this:
> myArr =
> myStr.split(String.fromCharCode(10)).join(String.fromCharCode(13)).split(Str
> ing.fromCharCode(13))
>
> I'm guessing I'm better off going the RegEx route, but I was wondering if
> there's a quicker, simpler way.
>
> Danny
>
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