How's this? /(((<|>)=?)|==)(-?\d+)/
Then the comparison operator is in result[1] and the number is in result[4]. You said "integer", so I threw in the optional negative sign. :) Dave On Thu, Mar 5, 2009 at 10:02 AM, Glen Pike <[email protected]>wrote: > Hi, > > How about: > > /([=><]+)([0-9]+)/ > > Check out "RegExr" by Grant Skinner - it's lovely. > > The problem with <= and >= is that there is "look behind" in the regex > controlled by these chars so the order of =>< seems to be important??? > Glen > > > Jiri wrote: > >> I would like some help on a regExp >> >> I have a string and want to split it into the first character being a >> <|>|<=|>=|== the second part being an int. >> >> so ">100" >> >> would return >> result[1] = '>' >> result[2] = 100 >> >> so "100" >> >> would return >> result[1] = 'undefined' >> result[2] = 100 >> >> Here is what I have so far, but it is killing me. >> >> var pattern:RegExp = /^(\d)?(^\d+)|(<?????>)/ >> var result:Object = pattern.exec(tConditionalString); >> >> I tried another approach but i am still figuring out how to do it. It goes >> something like this >> var pattern:RegExp = /^(>):((?(2)then|else)) >> >> >> Jiri >> >> >> >> >> _______________________________________________ >> Flashcoders mailing list >> [email protected] >> http://chattyfig.figleaf.com/mailman/listinfo/flashcoders >> >> >> > _______________________________________________ > Flashcoders mailing list > [email protected] > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders > _______________________________________________ Flashcoders mailing list [email protected] http://chattyfig.figleaf.com/mailman/listinfo/flashcoders
