thank ravi bt hv doubt
1.how can i convert it to object type ana at which line
2. if i recieve data as a list how can i idetify column from that here
one point is that in data column name are like
artist name ie. have space in between and are not in "" so i recieving
it a string and add "" round the column name

thanks
On Mar 23, 11:48 am, Ravi Mishra <[email protected]> wrote:
> Hi Akhil,
>
> I saw your code. You will have to convert your data to object type
> which is currently as a string.
>
> Why are your getting the data as a string from backend why not as a
> list of objects. That'll make your life a lot easier.
>
> -Ravi
>
> On Mar 23, 11:12 am, Akhil Agrawal <[email protected]> wrote:
>
> > this the complete sample code for the work i want to do
> > i have data as string from that i have to identify column and then
> > display corresponding data  in a grid
>
> > <?xml version="1.0"?>
> > <!-- dpcontrols/DataGridPassData.mxml -->
> > <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml";
> >    initialize="initData()">
> >    <mx:Script>
> >    <![CDATA[
> >       import mx.collections.*;
> >       import mx.controls.Alert;
> >       import mx.collections.ArrayCollection;
> >           import mx.controls.DataGrid;
> >           import mx.controls.dataGridClasses.DataGridColumn;
>
> > //data to be display in grid
> >  private var str:String="{'Artist Name':'Pavement', 'Album':'Slanted
> > and Enchanted', 'Price':'11.99'}*{'Artist Name':'Pavement',
> > 'Album':'Brighten the Corners', 'Price':'11.99'}";
>
> >       //   Alert.show(str,"string");
> >         private var DGArray:Array =str.split("*");
> >      //   Alert.show(DGArray[0].toString(),"array");
> >       [Bindable]
> >       public var initDG:ArrayCollection;
> >       //Initialize initDG ArrayCollection variable from the Array.
> >       //You can use this technique to convert an HTTPService,
> >       //WebService, or RemoteObject result to ArrayCollection.
> >       public function initData():void {
> >          initDG=new ArrayCollection(DGArray);
> >          var dcolumn:DataGridColumn=new DataGridColumn();
> >          Alert.show(DGArray[0].toString(),"dg");
> >          var row:Array=DGArray[0].toString().split(",");
> >          Alert.show(row.length.toString()+row[0].toString(),"row");
> >          var colName:String;
> >          var gridcolumns:Array=new Array();
> >          for(var i:int=0;i<row.length;i++)
> >                                 {
> >                                         
> > colName=row[i].toString().substr(1,row[i].toString().indexOf
> > (":")-1);
> >                                         
> > colName=colName.substring(1,colName.length-1);
> >                                         Alert.show(colName,"col name");
> >                                         dcolumn=new DataGridColumn();
> >                                         dcolumn.dataField=colName;
> >                         //              
> > Alert.show(dcolumn.dataField.toString(),"field");
> >                                         dcolumn.resizable=true;
> >                                         dcolumn.minWidth=200;
> >                                         gridcolumns.push(dcolumn);
>
> >                                 }
> >                                 myGrid.columns=gridcolumns;
> >                                 myGrid.dataProvider=initDG;
> >       }
> >    ]]>
> >    </mx:Script>
>
> >    <mx:DataGrid id="myGrid" width="350" height="200">
>
> >    </mx:DataGrid>
> > </mx:Application>
>
> > for this i am trying to parse the string to idengtify column Now plz
> > help me to do this
> > thank
>
> > Regards
> > Akhil Agrawal
>
> > On Mar 22, 6:06 pm, Ravi Mishra <[email protected]> wrote:
>
> > > send me the complete file....may be i can do something with that.
>
> > > -Ravi
>
> > > On Mar 22, 5:38 pm, Akhil Agrawal <[email protected]> wrote:
>
> > > > @ravi
> > > > it is not working . columns is an array that provide field name in
> > > > arraycollection for providing data to grid
>
> > > > On Mar 21, 11:17 am, Ravi Mishra <[email protected]> wrote:
>
> > > > > Dont declare the dcolumn as a global variable.....declare it locally
> > > > > in the function where you are running the for loop and then push this
> > > > > dcolumn to gridcolumns array and then finally assign this array to the
> > > > > columns property of datagrid.
>
> > > > > BTW what is columns in the for loop?
>
> > > > > -Ravi
> > > > > On Mar 20, 7:14 pm, Akhil Agrawal <[email protected]> wrote:
>
> > > > > > [Bindable]
> > > > > >                 private var queryResult:ArrayCollection=new 
> > > > > > ArrayCollection();
> > > > > >                 [Bindable]
> > > > > >                 private var gridcolumns:Array=new Array();
> > > > > >                 private var grid:DataGrid=new DataGrid();
> > > > > >                 [Bindable]
> > > > > >                 private var dcolumn:DataGridColumn=new 
> > > > > > DataGridColumn();
>
> > > > > > for(var i:int=0;i<columns.length;i++)
> > > > > >                                 {
>
> > > > > >                                 //      Alert.show(colName,"col 
> > > > > > name");
> > > > > >                                         dcolumn=new 
> > > > > > DataGridColumn(colName.toUpperCase()); //colname is
> > > > > > a string which is same as field in array collection
> > > > > >                                         dcolumn.dataField=colName;
> > > > > >                                         dcolumn.resizable=true;
> > > > > >                                         dcolumn.minWidth=200;
> > > > > >                                         gridcolumns.push(dcolumn);
>
> > > > > >                                 }
> > > > > >                                 this.grid.columns=gridcolumns;
> > > > > >                         var temp:ArrayCollection=new 
> > > > > > ArrayCollection(rows); // rows is an
> > > > > > array of rows as shown in previous post
> > > > > >          queryResult=temp;
> > > > > >                 this.grid.dataProvider=queryResult;
>
> > > > > > this is the code how i m  doing now plz help me in this regard
>
> > > > > > On Mar 20, 6:23 pm, Ravi Mishra <[email protected]> wrote:
>
> > > > > > > Can you pls send your complete code.....as I am not able to 
> > > > > > > understand
> > > > > > > what is gridColumns?
>
> > > > > > > GridColumns should be an Array and you should loop through each
> > > > > > > property of a row like this
>
> > > > > > > for each(var str:string in rowObject){
> > > > > > > // your code of creating and pushing the columns in GridColumns 
> > > > > > > array
>
> > > > > > > }
>
> > > > > > > then assign GridColumns to grid.columns
>
> > > > > > > HTH,
>
> > > > > > > -Ravi
>
> > > > > > > On Mar 20, 5:42 pm, Akhil Agrawal <[email protected]> wrote:
>
> > > > > > > > Hi all,
> > > > > > > > I have many rows in a arraycollection in tha form
> > > > > > > > {'Category ID':'null', 'Software Feature ID':'null', 'Event 
> > > > > > > > Date':'Tue
> > > > > > > > Mar 17 11:40:13 IST 2009', 'Event Type ID':'2102006'}
>
> > > > > > > > where category id and other are columns and creating 
> > > > > > > > datagridcolumn
> > > > > > > > like this
>
> > > > > > > > dcolumn=new DataGridColumn(colName.toUpperCase());
> > > > > > > > dcolumn.dataField=colName;
>
> > > > > > > > grid.columns=this.gridcolumns; // grid is an object of datagrid 
> > > > > > > > type
>
> > > > > > > > var temp:ArrayCollection=new ArrayCollection(rows);
>
> > > > > > > > this.grid.dataProvider=temp;
>
> > > > > > > > it is not displaying the data properply and displaying complete 
> > > > > > > > row as
> > > > > > > > written above in each column
> > > > > > > > how to fix it
>
> > > > > > > > thank you
>
> > > > > > > > regards
>
> > > > > > akhil agrawal
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