Let me code it, the codes should look like this
<mx:MyHBox>
<mx:Button label="Button 1" />
<mx:Button label="Button 2" />
<mx:Button label="Button 3" />
<mx:Button label="Button 4" />
</mx:MyHBox>
This needs to layout components in following manner
Button 4 | Button 3 | Button 2 | Button 1
If I add another button with addChild(new Button()); the new button
must appear before Button 4.
Thanks
On Sep 30, 2:38 pm, prem <[email protected]> wrote:
> However, I see the updateDisplayList() function in Box layout with the
> following loop
> for (i = 0; i < n; i++)
> {
> obj = IUIComponent(target.getChildAt(i));
> top = (h - obj.height) * verticalAlign +
> paddingTop;
> obj.move(Math.floor(left), Math.floor(top));
> if (obj.includeInLayout)
> left += obj.width + gap;
> }
> Does that not mean that we need to override updateDisplayList()
> function
>
> Thanks
>
> On Sep 30, 2:24 pm, rishi narang <[email protected]> wrote:
>
> > here are the steps:
>
> > i) create a class that extends UI component
> > ii) override createChildren method and in that method write all ur logic of
> > layout i.e. create for loop to layout sprites as containers by decrementing
> > there x values there by loop running in reverse order.
> > iii) populate those sprites with what ever data u want to add them to
>
> > hope this answers ur question.
>
> > On Wed, Sep 30, 2009 at 2:37 PM, prem <[email protected]> wrote:
>
> > > Guys,
> > > Yesterday I faced an interview question. How to create a custom
> > > component which behaves like an HBox but the children needs to be
> > > layed out in reverse order, i.e. From right to left and not from left
> > > to right. I answered, we need to override updateDisplayList to move
> > > the children, but the interviewer says its not the right answer
>
> > > Can anyone let me know how to do that?
>
> > > Thanks in advance
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