Thanks for the help folks.
I used the cos and sin formula for calculating the point on the
circumference and took that as a center for my smaller circles. Worked
perfect.
Thanks a lot.

On Jan 10, 12:20 am, Vaibhav Seth <[email protected]> wrote:
> Approach can be something like:
>
> Any point on the circle will be  (radius*cos(theta), radius*sine(theta))
>  where theta will range from 0 to 360 degree.
> Center coordinates of the main circle can be added to get the points on the
> circle circumference.
>
> i.e.,
>
> (radius*cos(theta) + centerX, radius*sine(theta)+centerY)
>
> Take the distance between these two points on circumferece as diameter for
> your smaller circles.
>
> Again its an approach, things may need to be worked out a little more.
>
> On Sat, Jan 9, 2010 at 2:07 PM, Saurabh Narula <[email protected]
>
>
>
> > wrote:
> > hi,
>
> > would these links help?
> > degrafa.org
>
> >http://www.brightpointinc.com/flexdemos/repeaterexample/degrafarepeat...
> >http://www.finflex.fi/projects/DegrafaPieMenu/
> >http://www.degrafa.org/samples/foundation.html
>
> > saurabh
>
> > On Sun, Jan 10, 2010 at 12:05 AM, Harshal <[email protected]> wrote:
>
> >> I have a interesting task at hand.
>
> >> I need to draw a circle. This is a easy part which can be achieved
> >> through the Graphics.drawCircle method.
>
> >> The part which i am puzzled at is, I need to draw several smaller
> >> circles on the border of this bigger circle. The center of the smaller
> >> circle will be one of the pixels on the border of the bigger circle.
>
> >> I searched the whole Flex API and couldn't find a way to get the
> >> details of the pixel points of the border of the circle.
>
> >> Any kind of help will be appreciated.
>
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> Thanks,
> Vaibhav Seth.
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